The Norton equivalent, loaded

This is the circuit from the lecture, running. Change it and the answer changes with it:

• Click any component value to edit it, or drag components to rearrange.
• The wrench opens a step-by-step analysis — it chooses a reference node and writes the node equations. Leave its Domain on the DC operating point for this deck.
• The crosshairs probe reads a node voltage or a branch current, so you can check any intermediate result rather than only the final answer.

Two equivalents, one load, one answer. Probe $V_o$ here and on the Thevenin version: both 1 V, both 1 mA in the load. Inside, the 5 k carries 1 mA in one and 0.2 mA in the other.